Engineering Thermodynamics Work And Heat Transfer __exclusive__

(Fundamental concepts, Laws, Flow and Non-flow processes).

You ended at the same altitude ($\Delta U$), but the $Q$ and $W$ were totally different. engineering thermodynamics work and heat transfer

Ideal gas: (V_1 = mRT_1/P_1 = (0.1)(0.287)(300)/(100) = 0.0861 m^3) Polytropic relation: (P_1V_1^n = P_2V_2^n \rightarrow V_2 = V_1(P_1/P_2)^1/n = 0.0861(100/400)^1/1.3 = 0.0295 m^3) Work: (W = (P_2V_2 - P_1V_1)/(1-n) = (400×0.0295 - 100×0.0861)/(1-1.3) = (11.8 - 8.61)/(-0.3) = -10.63 kJ) (work on system) Temperature: (T_2 = T_1(P_2/P_1)^(n-1)/n = 300(4)^0.3/1.3 = 429.8 K) (\Delta U = m c_v (T_2-T_1) = 0.1×0.718×(429.8-300) = 9.31 kJ) First Law: (Q = \Delta U + W = 9.31 + (-10.63) = -1.32 kJ) (heat rejected). (Fundamental concepts, Laws, Flow and Non-flow processes)

The field of is often described as the science of energy. While that sounds broad, it specifically focuses on how energy moves, changes form, and—most importantly—how we can use it to do something useful. The field of is often described as the science of energy

ΔE = Q - W

The net heat added to a system minus the net work done by the system equals the change in the system’s total internal energy.